(x-2)(x+5)=x^2-10

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Solution for (x-2)(x+5)=x^2-10 equation:


Simplifying
(x + -2)(x + 5) = x2 + -10

Reorder the terms:
(-2 + x)(x + 5) = x2 + -10

Reorder the terms:
(-2 + x)(5 + x) = x2 + -10

Multiply (-2 + x) * (5 + x)
(-2(5 + x) + x(5 + x)) = x2 + -10
((5 * -2 + x * -2) + x(5 + x)) = x2 + -10
((-10 + -2x) + x(5 + x)) = x2 + -10
(-10 + -2x + (5 * x + x * x)) = x2 + -10
(-10 + -2x + (5x + x2)) = x2 + -10

Combine like terms: -2x + 5x = 3x
(-10 + 3x + x2) = x2 + -10

Reorder the terms:
-10 + 3x + x2 = -10 + x2

Add '10' to each side of the equation.
-10 + 3x + 10 + x2 = -10 + 10 + x2

Reorder the terms:
-10 + 10 + 3x + x2 = -10 + 10 + x2

Combine like terms: -10 + 10 = 0
0 + 3x + x2 = -10 + 10 + x2
3x + x2 = -10 + 10 + x2

Combine like terms: -10 + 10 = 0
3x + x2 = 0 + x2
3x + x2 = x2

Add '-1x2' to each side of the equation.
3x + x2 + -1x2 = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
3x + 0 = x2 + -1x2
3x = x2 + -1x2

Combine like terms: x2 + -1x2 = 0
3x = 0

Solving
3x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '3'.
x = 0

Simplifying
x = 0

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